(6a-)5a=a^2-35a

Solution for (6a-)5a=a^2-35a equation:

(6a-)5a=a^2-35a

We move all terms to the left:

(6a-)5a-(a^2-35a)=0

We add all the numbers together, and all the variables

(+6a)5a-(a^2-35a)=0

We multiply parentheses

30a^2-(a^2-35a)=0

We get rid of parentheses

30a^2-a^2+35a=0

We add all the numbers together, and all the variables

29a^2+35a=0

a = 29; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·29·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*29}=\frac{-70}{58}
=-1+6/29
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*29}=\frac{0}{58}
=0
$